Hello,

firstofall, sorry, i know that it's a simple question (maybe stupid) but i cannot find out how to do.

1) a user on the website popup add an element to the Database using $.post WORKING
2) i want to refresh the SELECT in the form to include his element that the user just added without reload the page. Don't know how to do that.

1. <select id="wheel" name="wheel">
2. <?php
3.  $connection = new DBConnection();
4.  $requete = "SELECT nomService FROM structures WHERE serviceInterne = 0";
5. $result = $connection->query($requete);
6.          while($val = mysql_fetch_array($result)) { 
   
7.          $servicesExternes = $val['nomService'];
   
8.         print '<option value='.$servicesExternes.'>'.$servicesExternes.'</option>';
9.          }
10.          $connection -> end();
11.         ?>
12. </select>

And here the .js

1. $(document).ready(function(){
2.         $('#valider_ajout_structure').click(function(){  
               
               var nomStructure = $('#nomStructure').val();
               var ajouterStructureInterne = $('#ajouterStructureInterne').val();
               
           
                if (nomStructure.length == 0)
                {        
                    $('.jquery').html('<class="erreur">Vous n\"avez pas rentré le nom de la structure');  
                }
                else
                {  
                  $.post("/Iseult/ajouter/structure.php", { nomStructure : nomStructure, ajouterStructureInterne:ajouterStructureInterne });
   
   
   
   
   
   
   
   
   
   
   
   
3.                 I guess the code to update the SELECT will be here :p
                }  
            });  
      
    });
   
   
   
   
   
   
   

Thanks for your help