I had this working until I had to add a check box to the form.  Everything now works except the sql query.  My jquery looks like this (php to follow)

var dataString = 'name=' + name + ' & email=' + email + ' & note=' + note + ' & news=' + news;
        //alert (dataString);return false;
       
        $.ajax({
      type: "POST",
      url: "form/process.php",
      data: dataString,
      success: function() {
        $('#contact_form').html("<div id='message'></div>");
        $('#message').html("<center><h2>This is what we're all about &#45;<br /> here when you need us.</h2><p>We will be in touch with you as soon as possible.</p>")
        //.append("")
        .hide()
        .fadeIn(1000, function() {
          $('#message').append("<img src='images/logo_footer.png' />");
        });

And the php form looks like:

<?php

  //send email
  $name = $_REQUEST['name'] ;
  $email = $_REQUEST['email'] ;
  $note = $_REQUEST['note'] ;
  $news = $_REQUEST['news']
 
  $oncall = "On Call Legal Services";
  $message = "From: $name\r\nEmail: $email\r\nNote: $note"; 
  $rec_message = "Thank you $name for your interest in our services,\r\n We will be in touch with you momentaraly";
 
  mail( "name@email.com", "Name: $name ", $message, "From: $email" );

     
    $sql = "INSERT INTO `skwidge1_oncall`.`recipient` (`rec_name`, `rec_email`, `rec_note`, `rec_newsletter` ) VALUES ('$name', '$email',     '$note', '$news')";
   

    $query = mysqli_query($myConnection, $sql) or die (mysqli_error());
       
?>
 

For some reason the SQL is not getting inserted to the database and I feel like I am spending to much time gettng it to work.  Any help is appreciated.