[JQuery] Cleaning the code

[JQuery] Cleaning the code

Hello!I have implemented a small function using jQuery. Unfortunately, I'm still a noob, and I have certainly written a code longer and more repetitive than it should be. I would therefore ask your help in order to simplify it and improve it.

You can find what I have done at this address: http://www.flyareatest.altervista.org/p ... index.html

The part of the code that I would like to improve is:

jQuery(function($){
$(".toggler").click(function(){
$(".content").fadeToggle();
$(".content1").fadeOut("slow");
$(".content2").fadeOut("slow");
$(".content3").fadeOut("slow");
$(".content4").fadeOut("slow");
$(".content5").fadeOut("slow");
});
$(".toggler1").click(function(){
$(".content1").fadeToggle();
$(".content").fadeOut("slow");
$(".content2").fadeOut("slow");
$(".content3").fadeOut("slow");
$(".content4").fadeOut("slow");
$(".content5").fadeOut("slow");
});
$(".toggler2").click(function(){
$(".content2").fadeToggle();
$(".content").fadeOut("slow");
$(".content1").fadeOut("slow");
$(".content3").fadeOut("slow");
$(".content4").fadeOut("slow");
$(".content5").fadeOut("slow");
});
$(".toggler3").click(function(){
$(".content3").fadeToggle();
$(".content").fadeOut("slow");
$(".content1").fadeOut("slow");
$(".content2").fadeOut("slow");
$(".content4").fadeOut("slow");
$(".content5").fadeOut("slow");
});
$(".toggler4").click(function(){
$(".content4").fadeToggle();
$(".content").fadeOut("slow");
$(".content1").fadeOut("slow");
$(".content2").fadeOut("slow");
$(".content3").fadeOut("slow");
$(".content5").fadeOut("slow");
});
$(".toggler5").click(function(){
$(".content5").fadeToggle();
$(".content").fadeOut("slow");
$(".content1").fadeOut("slow");
$(".content2").fadeOut("slow");
$(".content3").fadeOut("slow");
$(".content4").fadeOut("slow");
});

This is a page with 6 links and 6 initially hidden div. By clicking on a link, the correspondant div appears, and it disappears by clicking on the link again thanks to the fadeToggle function. By clicking on a different link, the div (already opened) disappears with a fadeOut function.

Thank you all for your help!