[jQuery] tablesorter and parsers not defined error
Hopefully I am just overlooking something. I am attempting to use the
tablesorter plugin, and can't get past a parsers error. I am running
FireFox 3. I want to use the default values, and have then commented
out trying to debug the error. If I put the tablesorter() call at the
end, then my selectlists get populated. With tablesorter being first,
by selectlists are empty and I get the error message listed after the
code listing. Here is some of the code and the firebug information:
Code:
$(document).ready(function() {
// extend the default setting to always include the zebra widget.
// $.tablesorter.defaults.widgets = ['zebra'];
// extend the default setting to always sort on the first column
// $.tablesorter.defaults.sortList = [[4,0]];
// extend the default setting to always sort on the first column
// $.tablesorter.defaults.headers = {0:{ sorter: false}, 1:{sorter:
false}, 2:{ sorter: false}, 3:{ sorter: false}, 6:{ sorter: false}, 7:
{ sorter: false}};
// call the tablesorter plugin
$("#example").tablesorter();
// Populate School Select
$.getJSON("/BusRoutesPortlet/JSONSchool",function(j) {
var options = '';
options += '<option value="0">-- No School Selected --</option>';
for (var i = 0; i < j.length; i++) {
options += '<option value="' + j[i].optionValue + '"';
if (j[i].optionValue == sSch) {
options += ' selected="selected"';
}
options += '>' + j[i].optionDisplay + '</option>';
}
$("select#ctlSchool").html(options);
});
$.getJSON("/BusRoutesPortlet/JSONRoute",{school_id: sSch},function(j)
{
var options = '';
options += '<option value="0">-- No Route Selected --</option>';
for (var i = 0; i < j.length; i++) {
options += '<option value="' + j[i].optionValue + '"';
if (j[i].optionValue == sRte) {
options += ' selected="selected"';
}
options += '>' + j[i].optionDisplay + '</option>';
}
$("select#ctlRoute").html(options);
});
});
FireBug:
parsers is undefined
[Break on this error] (function($){$.extend({tablesorter:new function()
{var parsers=[],widgets=[];this...
jquery-tablesorte... (line 2)
Thank you! Ken