)
appears below it and then when you mouseout, it fades again.
I've found the best way to do it is that start with all the popups to
the side of the icons (so you can still hover over the icons and the
popups don't just block your way) and the popups begin as hidden
(opacity: 0). When you mouseover the icons, it sets the "top" and
"left" attribute of the popup to just below the icon and then it
slowly fades the popup from 0 to .7 and then vice versa when mouseout.
So, here is my code. You can view the product at the site below. Any
suggestions?
http://dev.quickscriptz.ca/v4/index.php
<script type="text/javascript"> //<![CDATA[
$(document).ready(function(){
// PNG transparency fix
$(document).pngFix();
// Basic variables
var outSpeed = "medium";
var outOpacity = .7;
var inSpeed = "fast";
var inOpacity = 1;
// Variables for icons & popups
var nowIcon, nowPopup, topPx, leftPx, topPxH, leftPxH, topPxS,
leftPxS;
// Loop it five times
for(var i = 1; i <= 5; i++){
// Variable for icon id
nowIcon = "#icon" + i;
nowPopup = "#popup" + i;
// Height from top of icon
topPx = $(nowIcon).css("top");
leftPx = $(nowIcon).css("left");
// Popup hidden position
topPxH = topPx - 10;
leftPxH = leftPx - 150;
// Popup showing position
topPxS = topPx + 100;
leftPxS = leftPx - 50;
// Start by hiding popups
$(nowPopup).css({top: topPxH});
$(nowPopup).css({left: leftPxH});
// Set opacity to zero (invisible)
//$(nowPopup).animate({opacity: 0});
// Mouse over event
$(nowIcon).mouseover(function(){
$(this).fadeTo(outSpeed, outOpacity);
$(nowPopup).css({top: topPxS});
$(nowPopup).css({left: leftPxS});
$(nowPopup).fadeTo(outSpeed, outOpacity);
})
// Mouse out event
$(nowIcon).mouseout(function(){
$(this).fadeTo(inSpeed, inOpacity);
$(nowPopup).fadeTo(inSpeed, 0);
})
}
})
//]]></script>