I am trying to apply a specific class to an ID if the href values of any of the children are equal to the current URL, in this case a list of links in a menu.  Here is a part of the relevant HTML and the jquery code I am trying.  Any help will be greatly appreciated!!

2.  <!-- notice the ID on the li - "aboutsection" -->
3. <ul id="mainnav" class="nav navbar-nav">
4.    
5.             <!-- About -->
6.             
7.            
8.             <li class="dropdown jsb-fw" id="aboutsection"><a href="#" 
9. 
   
10. data-hover="dropdown" data-delay="100" data-close-others="false" 
11. 
    
12. class="dropdown-toggle">About</a>
13.               <ul class="dropdown-menu">
14.             
15.               <li class="grid-output">
16.              
17.                 <div class="row">
18.                
19.               <div class="col-sm-3 about">
20.              
21.                     <h3 class="menuHeading">About US</h3>
22.                  <ul>
23.                        <li><a 
24. 
    
25. href="http://localhost:8500/mysite/pagetestcurrent.cfm">About this page</a></li>
26.                        <li><a 
27. 
    
28. href="http://localhost:8500/mysite/anotherpage.cfm">About another page </a></li>
29.                                     
30.                    </ul>
31.        </div>
32.       </div>
33.              </li>
34.            </ul>
35.         </li>   
36. 
    
37.   </ul>
38. 
    
39. <!-- if we are on any of the pages in the dropdown menu (which would 
40. 
    
41. be either'pagetestcurrent' or 'anotherpage' as in the example above as 
42. 
    
43. children of the about section), put a currentTab class on the above li 
44. 
    
45. with the ID 'aboutsection'-->
46. 
    
47. The jquery I am trying is this, but no luck - 
48. 
    
50. <script>
51. $('#aboutsection a').filter(function(){
52. var currentURL = window.location.href;
54.    if
55.    (
56.     currentURL == $(this).children('a').attr('href')
57. ) 
58.     {
59.        $('#aboutsection').addClass('currentTab');
60.    }
61.   
62. )};
63. 
    
64. 
    
65. </script>