var array1 = [
{ tagId: 1, tagName: 'tag 1' },
{ tagId: 2, tagName: 'tag 2' },
{ tagId: 3, tagName: 'tag 3' },
{ tagId: 4, tagName: 'tag 4' }
];
var array2 = [
{ tagId: 1, tagName: 'tag 1' },
{ tagId: 2, tagName: 'tag 2' },
{ tagId: 8, tagName: 'tag 8' }
];
var array3 = [
{ tagId: 1, tagName: 'tag 1' },
{ tagId: 0, tagName: 'tag 0' },
{ tagId: 9, tagName: 'tag 3' },
{ tagId: 12, tagName: 'tag 12' },
{ tagId: 13, tagName: 'tag 3' },
{ tagId: 14, tagName: 'tag 2' },
{ tagId: 6, tagName: 'tag 6' },
];
var common = [];
//The below code works for getting all common objects in first two array.But i want to get all common objects from all 3 arrays.
$.each(array1, function (index, item) {
var component = $(array2).filter(function () {
return this.tagId == item.tagId;
});
if (component[0] != undefined) {
common.push(component)
}
});
alert(common.length);//2