post select value

post select value

Hello!

I have this short code:


  // JS code

   $("form#submit").submit(function() {
   var fname     = $('#fname').attr('value');
   var lname     = $('#lname').attr('value');
      $.ajax({
         type: "POST",
         url: "settings.php",
         data: "fname="+ fname +"& lname="+ lname,
         success: function(){
            $('form#submit').hide();
            $('div.success').fadeIn();
         }
      });
   return false;
   });

// php code

echo "<div class='showhide$i'>.........<form id='submit$i' method='post'><input type='hidden' name='lname' id='lname' class='text' value='$valuei'><input type='hidden' name='fname' id='fname' class='text' value='$fm_linkaz'></div><input name='add'   type='image' id='add'......</form></td></tr></table></div>";

if (isset($_POST['fname'])){
       $fname        = htmlspecialchars(trim($_POST['fname']));
        DO SOMETHING...
}


With this i can post "fname and lname" value...

But add a select to the echo:

echo "<div class='showhide$i'>.........<form id='submit$i' method='post'><input type='hidden' name='lname' id='lname' class='text' value='$valuei'><input type='hidden' name='fname' id='fname' class='text' value='$fm_linkaz'></div><input name='add'   type='image' id='add'......

echo "<select name=dropdown_list id='oname'><option value''>$rokoni_tipusok</option>";for($i=0; $i < count($kapcs_tip); $i++){  echo "<option value='$kapcs_tip[$i]'>$kapcs_tip[$i]</option>";
}echo "</select>";...........


How can i post the Select value (oname), same as fname and lname?

Could anyone help me to change the code?!

Thank you very much.