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$.ajax, json returning html in response in PHP
in Using jQuery
•
11 years ago
I have a PHP page that has a button to Delete a customer. The button code uses $.ajax to call the page that "deletes" the customer and returns a JSON object on success or failure. The problem is the JSON response includes html from my two includes. Here is the code from the main page:
Here is the code from the called page:
Also, am I indicating success/failure the correct way? I wonder because I don't know how my calling program knows to process the error function. What is the correct way to indicate an error or failure?
- $("#btnDelete").click(function(){
if (confirm("Are you sure you want to delete this customer and ALL their records?")) {
$.ajax({
type: "POST",
url: "/includes/delete_customer.php",
data: "cust_id=<?php echo $custno; ?>",
dataType : "json",
success: function(msg){
alert("Success: " + msg);
},
error: function(XMLHttpRequest, textStatus, errorThrown){
alert("Failure: " + errorThrown);
}
});
top.location = "/pages/edit_customer_list.php";
}
});
Here is the code from the called page:
- <?php
header("Content-type: application/json");
include_once($_SERVER["DOCUMENT_ROOT"]."/includes/main.php");
include_once($_SERVER["DOCUMENT_ROOT"]."/includes/dbconnect.php");
// Don't actually delete, just mark as inactive
$query = "UPDATE customers SET active=FALSE WHERE id=".$_POST["cust_id"];
$result = mysql_query($query);
if ($result) {
$return['success'] = true;
$return['error'] = false;
$return['msg'] = "This customer has been successfully deleted.";
} else {
$return['success'] = false;
$return['error'] = true;
$return['msg'] = mysql_error();
}
mysql_free_result($result);
echo json_encode($return);
?>
Also, am I indicating success/failure the correct way? I wonder because I don't know how my calling program knows to process the error function. What is the correct way to indicate an error or failure?
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