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Getting Started

Array variable inside contains()

in Getting Started • 4 years ago

var good = [
"Label1",
"Label2",
"Label3"
];
var goodlen = good.length;
var i;
var x = good[i];
for(i = 0; i < goodlen; i++){
$("span:contains('"+ x +"')").hide();
}
<span class='xxx'>Label1</span>
<span class='xxx'>Label2</span>
<span class='xxx'>Label3</span>
I cant tell whats wrong here. I actually had it working and now Im not sure what happened. I cant figure out what the correct syntax is of putting the x variable inside the jquery line. if you look I have it with double quotes inside single quotes --just the + x + part I mean. Which I think is really odd but yet it changes to look correct(coloring) inside my editor. I checked stackoverflow and seen it done this way. This has me baffled. Any suggestions?

1

Replies(7)

jakecigar

Re: Array variable inside contains()

4 years ago

Did you put your code inside a ready callback? .ready() | jQuery API Documentation

JΛ̊KE

Re: Array variable inside contains()

4 years ago

I have it inside this

(function() {
})();

jakecigar

Re: Re: Array variable inside contains()

4 years ago

That is a generic closure. Not a ready callback.

JΛ̊KE

Re: Array variable inside contains()

4 years ago

I got it in this now...

```
$( document ).ready(function() {
```

})();

no change.

jakecigar

Re: Array variable inside contains()

4 years ago

for (i = 0; i < goodlen; i++) {
var x = good[i];
$("span:contains('" + x + "')").hide();
}

https://jsfiddle.net/jakecigar/w2y0o5va/ <--

JΛ̊KE

Re: Array variable inside contains()

4 years ago

wow. Thanks jake I totally overlooked that!

jakecigar

Re: Re: Array variable inside contains()

4 years ago

So did I. Next time make a fiddle of your code, so we can see it fail.

JΛ̊KE