jQuery Forum

There is no way for anyone here to know how your form, table and pagination all work together and how you are interacting with server.

here are a exemple

http://darabani.net/ci21/segunda_mano/anuncios

you can see the pagination is work...

but if you select a option from first select for example 'COCHES'  then you have a 12 results and 2 page

if you press a 2 page on pagination return all result because not passed the select valor

i don't want to pass this value from url(type get) because is not efficient and y have a lot of camp on the form

i want to pass all the value of the form when press a second page of pagination ( push the form on click on button pagination)


Thanks, amic.

I want to send the form when change every time the page pagination.
When pres 2 send form on press 3 send form again on press 2 send again.......

Thanks, amic.

It's work.

Whit a little change en mi controller and the final jQuery for me:

  jQuery('#paginator a').click(function(){
      var form=jQuery('#third2')
      form.find('[name="page"]').val( jQuery(this).text());
      form.submit();
      return false;
 });
 
 jQuery('form#third2 :input').change(function(){
     jQuery(this).closest('form').find('[name="page"]').val(1);
 });

You are the best, thank you very much.

P.S.
    What stands for this cod:
      jQuery('form#third2 :input').change(function(){
        jQuery(this).closest('form').find('[name="page"]').val(1);
      });
   if i delete it, its working the same.

keep in mind that will fail if javascript disabled, which is why I made the first suggestion of session variables