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kflorence

$.inObject

Implemented

Maybe later
Under review
In-progress
Implemented
Will not implement

in Developing jQuery Core • 13 years ago

I think it would be convenient to have a method for testing whether or not a value exists in an object (of course you can use the long-hand version of this, but this seems more intuitive, especially when an inArray function exists):

$.inObject = function(object, value) {
return (typeof object[value] === 'undefined' ? false : true);
};

Replies(3)

jeresig

Re: $.inObject

13 years ago

Why not just do?

if ( value in object ) { ... }

Nice and short and works just fine.

kflorence

Re: Re: $.inObject

13 years ago

Sweet, wasn't aware you could use "in" like that!

dbjdbj

Re: Re: $.inObject

13 years ago

Which version you prefer ?

function inside1 ( o, x ) { return o[x]; }
function inside2 ( o, x ) { if (x in o) return true; else return false; }
function inside3 ( o, x ) { if (x in o) if (Object.prototype.hasOwnProperty.call(o,x)) return true; else return false; }
inside1([3,2,1], "toString")
/*returns: function toString() { [native code]} */
inside2([3,2,1], "toString")
/* returns: true */
inside3([3,2,1], "toString")
/* returns: false */

Meaning: do you want/need properties which are "inherited", or more appropriatelly up on the prototype chain ?

--DBJ

travesty3

Re: $.inObject

9 years ago

I know this is old, but I think there's an error in the thought process here. The equivalent to the $.inArray() function would need to check to see if the value exists in the object, not if the key exists.

So correct me if I'm wrong, but I believe an equivalent function would have to look more like this:

$.inObject = function(value, obj) {
var foundKey;
$.each(obj, function(key, val) {
if (value === val) {
foundKey = key;
return;
}
});
return foundKey;
};

jsFiddle

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$.inObject

Implemented

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