jQuery Forum

you just need to change $.blockUI to $('#mytagid').bockUI. The sasme
with unblock call.
George

hi Georges,
yes, but the problem is that i don't know which element is concerned
by the call (unless i hardcode it each time of course, but that's what
i would like to avoid).
Thanks for your input nonetheless.

Ok, now i am not sure what exactly is a problem... sorry.
You can call this code
$().ajaxStart($('#mydiv').blockUI).ajaxStop($('#mydiv').unblockUI);
as many time as you want.
It only changes which function will be called once AJAX is doing the
call..
So right before doing your ajax call to the
$().ajaxStart($('#mydiv').blockUI).ajaxStop($('#mydiv').unblockUI);
Or you can create your own function wrapper that does the AJAX call
function DoTheCall(element)
{
$().ajaxStart($(element).blockUI).ajaxStop($(element).unblockUI);
$.ajax(.....); //the actual ajax call....
}
George,

> $().ajaxStart($.blockUI).ajaxStop($.unblockUI);
>
> Now, i would like to know if it is possible to customize this call so
> that the concerned element shows blockUI, instead of the whole page ?
To block only a single element you would use "block" instead of
"blockUI".
$('#myDiv').block();
...
$('#myDiv').unblock();
To make it generic, somewhere some code has to set the context for
what needs to be blocked. You didn't show any of the other code
you're using so it's hard to say. But in pseudo-code it would look
like:
$().ajaxStart(function() {
var el = get the element that needs to be blocked
$(el).block();
}).ajaxStop(function() {
var el = get the element that needs to be un blocked
$(el).unblock();
});