Response title
This is preview!
<input type="text" id="name" />
<div id="name_feedback"></div>
$('#name').keyup(function(){
var name = $('#name').val();
$.post('proces.php'), {name:name}, function(data) {
$('#name_feedback').html(data);
});
});
<?php
if(isset($_POST['name'])){
$name = $_POST['name'];
echo $name; //or mysql_query..... ?>
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