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State of slideToggle()

in Using jQuery • 13 years ago

Is there a way to tell the state of slideToggle?
My problem is I have two buttons that change a div and also toggle it open/close.
But if you click one button then click the other, the changes take effect and then it will close.

So is there something like if(slideToggle() == open) or something along those lines?

Replies(3)

kbwood.au

Re: State of slideToggle()

13 years ago

The current state is determined by this test: $(this).is(":hidden").

sagmahajan

Re: State of slideToggle()

10 years ago

Hello

I one of my project I have used following code in click event, it alerts FALSE two times,,

as per you said it should alert Once TRUE and once FALSE.

Code:

$('.box_c_heading .wToogle').click(function(){

var status=$(this).is(":hidden");

alert(status);

$(this).parent().next().slideToggle('fast');

var status=$(this).is(":hidden");

alert(status);

});

cliftonm

Re: State of slideToggle()

9 years ago

If anyone reads this (given the above was posted a year ago) the reason the fellow above is getting FALSE twice is because:

After calling slideToggle(), hidden ALWAYS returns false regardless of the state.

(Besides the fact that it looks like sagmahajan is testing for hidden on the wrong control.

In order to work around the issue, I have to obtain the state FIRST:

var hidden = $(".property_group0").is(":hidden");
$(".property_group0").slideToggle('slow');
if (!hidden) {...}

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