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偉雄陳

The value of spinner inside table cannot be got by $_POST

in Using jQuery UI • 6 years ago

I am using jquery-ui with spinner.

I found that the value of spinner inside table cannot be got by $_POST.

<table>

......

</table>

In this situation, spinner is discarded.

Would anyone try this and solve the problem?

Replies(3)

coldfusio..

Re: The value of spinner inside table cannot be got by $_POST

6 years ago

http://stackoverflow.com/questions/5967564/form-inside-a-table

Show us exactly how your table with the input nested is structured

Leave a comment on coldfusionguy's reply

偉雄陳

Re: The value of spinner inside table cannot be got by $_POST

6 years ago

I found the solution now.

Spinner doesn't work when <form></form> are inside <table></table>.

<table>

<form>

,,,,,,

</form>

</table>

Spinner works when <form></form> are inside <table></table>.

<form>

<table>

,,,,,,

</table>

</form>

Re: The value of spinner inside table cannot be got by $_POST

6 years ago

Ok Great!

If you ever had questions about html markup especially. you can always use this to check:

http://validator.w3.org/#validate_by_input

Leave a comment on coldfusionguy's reply

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{"z34005662":[14737000005635536,14737000005635791],"z18738316":[14737000005633863,14737000005633865]}

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The value of spinner inside table cannot be got by $_POST

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Re: The value of spinner inside table cannot be got by $_POST

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Re: The value of spinner inside table cannot be got by $_POST

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