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stian.jqu..

What is the return value of .wrap() ?

in Using jQuery • 12 years ago

Hi,

I took a wild guess and thought the following code would return the new wrapper as an object:

var objWrapper = $("p").wrap("<div />");

and that I could continue working with objWrapper, for example:

objWrapper.css("padding", "5px");

but I couldn't. What I need to do is:

$("p").wrap("<div id='wrapper' />");
var objWrapper = $("#wrapper");
objWrapper.css("padding", "5px");

This, to me, looks like an extra roundtrip to the DOM. So my question is: Is this by design, or am I doing something wrong?

Stian

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jules

Re: What is the return value of .wrap() ?

12 years ago

$("p").wrap("<div />") returns $("p") instead of $("<div/>"). I think it is make sense to return the original object instead of the new one.

If you want to access the new div, use this

$("p").wrap("<div/>").parent().css("padding","5px");

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