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Why the hell this is not working properly?
in Developing jQuery Plugins
•
10 years ago
I have a jQuery plugin that returns an instance of a regular javascript class. Inside this class I have a public method setting the style of the selector element with jquery.
Example: http://jsfiddle.net/v4hcC/1/
As you can see jquery doesnt set the css of the element when it receives the undefined argument (value). But if I remove the second argument (value) jquery sets normally the css into the element.
Example: http://jsfiddle.net/mb8Je/3/
Obviously, in the second example it will not set the border at all (no second argument). But the first example now works. Why?
UPDATE: I know that if I do this it will work
UPDATE:
This is not a matter of test the value argument inside the method, but make the thing work without any modification in its structure. Since the css() receives 2 arguments and my method passes the identical 2, the method css() should behave equally in both, but thats not what is happening. Why?
Example: http://jsfiddle.net/v4hcC/1/
As you can see jquery doesnt set the css of the element when it receives the undefined argument (value). But if I remove the second argument (value) jquery sets normally the css into the element.
Example: http://jsfiddle.net/mb8Je/3/
Obviously, in the second example it will not set the border at all (no second argument). But the first example now works. Why?
UPDATE: I know that if I do this it will work
-
if($.isPlainObject(style)) {
options.elemento.css(style);
} else {
options.elemento.css(style, value);
}
- options.elemento.css(style, value);
UPDATE:
This is not a matter of test the value argument inside the method, but make the thing work without any modification in its structure. Since the css() receives 2 arguments and my method passes the identical 2, the method css() should behave equally in both, but thats not what is happening. Why?
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